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Question: The electrostatic energy of nucleus \({}_{3}^{8}Li\) is given as-...

The electrostatic energy of nucleus 38Li{}_{3}^{8}Li is given as-

A

3 MeV

B

8 MeV

C

15 MeV

D

20 MeV

Answer

3 MeV

Explanation

Solution

Electrostatic self energy is

EC = 35\frac { 3 } { 5 } R = R0A1/3 = 1.2 × 10–15 × (8)1/3

= 1.2 × 10–15 × 2 = 2.4 × 10–15 m

EC = 3/5×9×109×(3)2×(1.6×10−19)22.4×10−15×1.6×10−19\frac { 3 / 5 \times 9 \times 10 ^ { 9 } \times ( 3 ) ^ { 2 } \times \left( 1.6 \times 10 ^ { - 19 } \right) ^ { 2 } } { 2.4 \times 10 ^ { - 15 } \times 1.6 \times 10 ^ { - 19 } }

= 35×9×109×9×1.6×10−42.4\frac { \frac { 3 } { 5 } \times 9 \times 10 ^ { 9 } \times 9 \times 1.6 \times 10 ^ { - 4 } } { 2.4 }

= 2×81×109×10−45\frac { 2 \times 81 \times 109 \times 10 ^ { - 4 } } { 5 }= 16 × 2 × 10+5 eV

EC = 32 × 105 eV

= 3.2 × 105 eV

EC = 3.2 MeV