Question

The electronic configuration of four atoms are given in brackets: $L\left(1s^{2} 2s^{2} 2p^{1}\right);$ $M\left(1s^{2} 2s^{2} 2p^{5}\right);$ $Q\left(1s^{2} 2s^{2} 2p^{6} 3s^{1}\right);$ $R\left(1s^{2} 2s^{2} 2p^{2}\right);$ The element that would most readily form a diatomic molecule is

• A. $Q$
• B. $M$
• C. $R$
• D. $L$

Answer 1

Answer: (B)

$M$

Answer 2

By sharing of $1$ electron each, both the atoms of $M$ will get a completed octet.