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Question: The electronic configuration of Cr is (atomic number = 24): (a)- \(1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3...

The electronic configuration of Cr is (atomic number = 24):
(a)- 1s22s22p63s23p64s24p41{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}4{{s}^{2}}4{{p}^{4}}
(b)- 1s22s22p63s23p63d61{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{6}}
(c)- 1s22s22p63s23p63d54s11{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{5}}4{{s}^{1}}
(d)- 1s22s22p63s23p64s14p51{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}4{{s}^{1}}4{{p}^{5}}

Explanation

Solution

Cr is the chromium element that belongs to the d-block. The last electron enters into the d-subshell. The d-orbital has the property of extra-stability because of a half-filled or fully-filled subshell.

Complete step by step answer:
Cr is the chromium element and it belongs to transition elements and is the element of d-block.
The atomic number of chromium is 24 and it belongs to the first series of the d-block.
According to the Aufbau principle the order of filling the electron in the orbital according to their increasing energies is: 1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p 7s\text{1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p 7s}
So, according to this order of filling the configuration of chromium must be:
1s22s22p63s23p64s23d41{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}4{{s}^{2}}3{{d}^{4}}.
But this is not the correct configuration of chromium.
The correct configuration of chromium can be explained by:
There are some exceptions in the first series in the electronic configuration of chromium (atomic no. = 24). It must be noted that unlike other elements of the first transition series, the chromium has 1 electron and is 4sorbital4s-orbital. This is due to the gain of additional stability by the atom by having a half-filled configuration (because the d-orbital has 5 subshells and each subshell has 1 electron) of 3dorbital3d-orbital. The 3dorbital3d-orbitalin case of chromium gets exactly half-filled with configuration of 3d54s13{{d}^{5}}4{{s}^{1}}. So, the configuration of chromium is 1s22s22p63s23p63d54s11{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{5}}4{{s}^{1}}.

Hence, the correct answer is an option (c)- 1s22s22p63s23p63d54s11{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{5}}4{{s}^{1}}.

Note: In the first series of the transition metals the copper atom has also an exception in its configuration. The configuration of copper is 1s22s22p63s23p63d104s11{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{10}}4{{s}^{1}}. This is because the d-subshell has complete 10 electrons that have extra stability.