Question

The electronic configuration of an element is $1s^2,2s^2 2p^6,3s^2 3p^3$. What is the atomic number of the element, which is present just below the above element in the periodic table?

• A. 33
• B. 34
• C. 36
• D. 49

Answer 1

Answer: (A)

33

Answer 2

The element which present just below this element will have outermost electronic configuration as $4s^2 4p^3$, so its full electronic configuration is $1s^2, 2s^2 2p^6, 3s^2 3p^6, 4s^2,$ $3d^{10}, 4p^3$ and hence, its atomic number is 33.