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Chemistry Question on Electronic Configurations Of Elements And The Periodic Table

The electronic configuration of a dipositive ion M2+M^{2+} is 2, 8, 14 and its mass number is 56. The number of neutrons present is

A

32

B

42

C

30

D

34

Answer

30

Explanation

Solution

The electrons in dipositive ion (M12+)(M^{12+}) is 2+8+14=242 + 8 + 14 = 24 Electrons = Protons in M=26M = 26 ∴\therefore Neutrons =56−26=30= 56 - 2 6 = 30.