The electronegativities of (C, N, Si) and (P) are in the ord... | Chemistry | SolveeIt

Question

The electronegativities of $C, N, Si$ and $P$ are in the order of

$P < Si < C < N$

$Si < P < N < C$

$Si < P < C < N$

$P < Si < N < C$

Answer

$Si < P < C < N$

Explanation

Solution

Electronegativity increases as we more left to right in a period and decreases as we move down in the group. (i) $C$ and $N$ belong to the same period. Hence $N$ has more electronegativity than carbon (C). (ii) In the same way $P$ is more electronegative than Si (iii) As Si is below the carbon is 14th group the electronegativity of carbons is more than of Si.

Chemistry Question on Classification of elements & periodicity in properties

Solution