Question

The electron affinity values (in $kJmol^{- 1}$) of three halogens $X,Y$ and $Z$ are respectively – 349, – 333 and – 325. Then $X,Y$ and $Z$ are respectively

• A. $F_{2},Cl_{2}$ and $Br_{2}$
• B. $Cl_{2},F_{2}$ and $Br_{2}$
• C. $Cl_{2},Br_{2}$ and $F_{2}$
• D. $Br_{2},Cl_{2}$ and $F_{2}$

Answer 1

Answer: (B)

$Cl_{2},F_{2}$ and $Br_{2}$

Answer 2

In IB group all elements are metals.