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Question: The electrochemical equivalent of a metal is \(3.3 \times 10^{- 7}kg/coulomb\). The mass of the met...

The electrochemical equivalent of a metal is

3.3×107kg/coulomb3.3 \times 10^{- 7}kg/coulomb. The mass of the metal liberated at the cathode when a 3 A current is passed for 2 seconds will be

A

19.8×107kg19.8 \times 10^{- 7}kg

B

9.39×107kg9.39 \times 10^{- 7}kg

C

6.6×107kg6.6 \times 10^{- 7}kg

D

1.1×107kg1.1 \times 10^{- 7}kg

Answer

19.8×107kg19.8 \times 10^{- 7}kg

Explanation

Solution

m=Zit=3.3×107×3×2=19.8×107kgm = Zit = 3.3 \times 10^{- 7} \times 3 \times 2 = 19.8 \times 10^{- 7}kg