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Question

Mathematics Question on Linear Equations

The electricity bill of a certain establishment is partly fixed and partly varies with the number of units of electricity consumed. Whenin a certain month 540 units are consumed, the bill is 1800. In another month 620 units are consumed and the bill is 2040. In yetanother month 500 units are consumed. The bill for that month would be

A

1680

B

1560

C

1840

D

1950

Answer

1680

Explanation

Solution

let fixed unit be x and cost of each unit be y
540y + x =1800 .............(1)
620y + x = 2040.............(2)
Solving both the equation we will have y=3
Now placing y value in any of the equation give
x=180 (fixed value)
So now we will have
Bill = 180 +(500×\times3)
=1680.
So the correct option is (B)