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Question

Physics Question on Current electricity

The electrical permittivity and magnetic permeability of free space are respectively εo{{\varepsilon }_{o}} and μ0{{\mu }_{0}} . The corresponding value for a medium is:

A

μoεoμε\sqrt{\frac{{{\mu }_{o}}{{\varepsilon }_{o}}}{\mu \varepsilon }}

B

(μoεoμε)3/2{{\left( \frac{{{\mu }_{o}}{{\varepsilon }_{o}}}{\mu \varepsilon } \right)}^{3/2}}

C

μεμoεo\sqrt{\frac{\mu \varepsilon }{{{\mu }_{o}}{{\varepsilon }_{o}}}}

D

μoεoμε\frac{{{\mu }_{o}}{{\varepsilon }_{o}}}{\mu \varepsilon }

Answer

μεμoεo\sqrt{\frac{\mu \varepsilon }{{{\mu }_{o}}{{\varepsilon }_{o}}}}

Explanation

Solution

μ0\mu_{0} is called permeability of free space and ε0\varepsilon_{0} is called permittivity of free space.
From Huygens wave theory n= speed of light in vacuum (c) speed of light in medium (v) n=\frac{\text { speed of light in vacuum }(c)}{\text { speed of light in medium (v) }}
Since, c=1μ0ε0,v=1με.c=\frac{1}{\sqrt{\mu_{0} \varepsilon_{0}}}, v=\frac{1}{\mu \varepsilon} .
n=μεμ0ε0\therefore n=\sqrt{\frac{\mu \varepsilon}{\mu_{0} \varepsilon_{0}}}

So, the correct option is (C): μεμoεo\sqrt{\frac{\mu \varepsilon }{{{\mu }_{o}}{{\varepsilon }_{o}}}}