Question: The electric potential $V$ is given as a function of distance $x$ (metre) by \(V = (5x^{2} + 10x...

Question

The electric potential $V$ is given as a function of distance $x$ (metre) by $V = (5x^{2} + 10x - 9)volt$ . Value of electric field at $x = 1$ is

Answer 1

$E = - \frac{dV}{dx} = - \frac{d}{dx}(5x^{2} + 10x - 9) = - 10x - 10$

∴ $(E)_{x = 1} = - 10 \times 1 - 10 = - 20V/m$

Question: The electric potential \(V\) is given as a function of distance \(x\) (metre) by \(V = (5x^{2} + 10x...