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Question

Physics Question on Electric Field

The electric potential VV at any point (x,y,z)(x, y, z), all in metres in space is given by V=4x2V = 4x^2 volt. The electric field at the point (1,0,2)(1, 0, 2) in volt/meter, is

A

8 along negative X-axis

B

8 along positive X-axis

C

16 along negative X-axis

D

16 along positive X-axis

Answer

8 along negative X-axis

Explanation

Solution

E=[i^Vx+j^Vy+k^Vz]\vec{ E }=-\left[\hat{ i } \frac{\partial V }{\partial x }+\hat{ j } \frac{\partial V }{\partial y }+\hat{ k } \frac{\partial V }{\partial z }\right] E=[i^(8x)]\vec{ E }=-[\hat{ i }(8 x )] E(1,0,2)=8i^\vec{ E }_{(1,0,2)}=-8 \hat{ i } So electric field is 8 along negative xx -axis.