Question

The electric potential at the surface of an atomic nucleus (Z = 50) of radius $9 \times 10^{5}V$ is

• A. 80 V
• B. $8 \times 10^{6}V$
• C. 9 V
• D. $9 \times 10^{5}V$

Answer 1

Answer: (B)

$8 \times 10^{6}V$

Answer 2

$V = 9 \times 10^{9} \times \frac{ne}{r} = 9 \times 10^{9} \times \frac{50 \times 1.6 \times 10^{- 19}}{9 \times 10^{- 15}} = 8 \times 10^{6}V$