Question

The electric potential at a point in free space due to charge Q coulomb is Q × 10¹¹ volts. The electric field at that point is-

• A. 4pe₀Q × 10²⁰ volt/m
• B. 12pe₀Q × 10²² volt/m
• C. 4pe₀Q × 10²² volt/m
• D. 12pe₀Q × 10²⁰ volt/m

Answer 1

Answer: (C)

4pe₀Q × 10²² volt/m

Answer 2

= Q × 10¹¹ \ $\frac { 1 } { \mathrm { R } }$ =

\ E = = kQ $\left( \frac { 10 ^ { 11 } } { \mathrm { R } } \right) ^ { 2 }$ = 4pĪ₀Q × 10²² V/m