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Question

Physics Question on Electric charges and fields

The electric flux passing through aa cube of side aa , which holds a charge qq at one of its corners is

A

qε0\frac{q}{\varepsilon_{0}}

B

q8ε0\frac{q}{8\varepsilon_{0}}

C

q4ε0\frac{q}{4\varepsilon_{0}}

D

q2ε0\frac{q}{2\varepsilon_{0}}

Answer

q8ε0\frac{q}{8\varepsilon_{0}}

Explanation

Solution

Eight identical cubes are required so that the given charge qq appears at the centre of the bigger cube
Thus, the electric flux passing through the given cube is
ϕ=18(qε0)\phi=\frac{1}{8} \left(\frac{q}{\varepsilon_{0}}\right)
=q8ε0=\frac{q}{8\varepsilon_{0}}