Question

The electric flux for Gaussian surface A that enclose the charged particles in free space is (given q₁ = –14 nC, q₂ = 78.85 nC, q₃ = – 56 nC)

• A. 10³ Nm² C^–1
• B. 10³ CN^-1 m^–2
• C. 6.32 × 10³ Nm² C^–1
• D. 6.32 × 10³ CN^-1 m^–2

Answer 1

Answer: (A)

10³ Nm² C^–1

Answer 2

Sol. Flux is due to charges enclosed per $\varepsilon_{0}$

∴ Total flux = $( - 14 + 78.85 - 56)nC/\varepsilon_{0}$

$= 8.85 \times 10^{- 9}C \times \frac{4\pi}{4\pi\varepsilon_{0}} = 8.85 \times 10^{- 9} \times 9 \times 10^{9} \times 4\pi$

$= 1000.4Nm^{2}/C$ i..e. $1000Nm^{2}C^{- 1}$