Solveeit Logo

Question

Question: The electric fields part of an electromagnetic wave I vacuum is E=3.1 \(\mathrm { C } ^ { - 1 }\) \(...

The electric fields part of an electromagnetic wave I vacuum is E=3.1 C1\mathrm { C } ^ { - 1 } cos[(1.8radm1)y+(5.4×188rads1)t]i^\cos\left\lbrack (1.8radm^{- 1})y + (5.4 \times 18^{8}rads^{- 1})t \right\rbrack\widehat{i}, the amplitude of magnetic field part of the given wave is :

A

2×108T2 \times 10^{- 8}T

B

1.03×108T1.03 \times 10^{- 8}T

C

4.22×108T4.22 \times 10^{- 8}T

D

5×108T5 \times 10^{- 8}T

Answer

1.03×108T1.03 \times 10^{- 8}T

Explanation

Solution

: Comparing equation (i) and (ii) we get

}{\therefore B_{0} = \frac{E_{0}}{c} = \frac{3.1}{3 \times 10^{8}} = 1.03 \times 10^{- 8}T}$$