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Question: The electric fields part of an electromagnetic wave I vacuum is E=3.1 \(\mathrm { C } ^ { - 1 }\) \(...

The electric fields part of an electromagnetic wave I vacuum is E=3.1 C1\mathrm { C } ^ { - 1 } cos[(1.8radm1)y+(5.4×188rads1)t]i^\cos\left\lbrack (1.8radm^{- 1})y + (5.4 \times 18^{8}rads^{- 1})t \right\rbrack\widehat{i} the frequency corresponding to the given part of electromagnetic wave is :

A

5.4×108Hz5.4 \times 10^{8}Hz

B

8.6×107Hz8.6 \times 10^{7}Hz

C

3.2×108Hz3.2 \times 10^{8}Hz

D

4.8×107Hz4.8 \times 10^{7}Hz

Answer

8.6×107Hz8.6 \times 10^{7}Hz

Explanation

Solution

: Frequency,

υ=ω2π=5.4×108×72×22=8.6×107Hz\upsilon = \frac{\omega}{2\pi} = \frac{5.4 \times 10^{8} \times 7}{2 \times 22} = 8.6 \times 10^{7}Hz