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Physics Question on Electromagnetic induction

The electric field vector oscillates according to the equation E→=4sin[1.8y+(5.4×106)t]k^\overrightarrow E = 4sin[1.8y +(5.4×10^6)t]\hat k. The equation of magnetic field vector is:

A

B→=1.33×10−8sin[1.8y+(5.4×106)t]ı^\overrightarrow B=1.33×10^{-8}sin [1.8y +(5.4×10^6)t]î

B

B→=4sin[1.8y+(5.4×106)t]j^\overrightarrow B=4sin[1.8y+(5.4 \times 10^6)t]\hat j

C

B→=1.33×10−8sin[1.8y+(5.4×106)t]k^\overrightarrow B=1.33×10^{-8} sin[1.8y+(5.4×10^6)t]\hat k

D

B→=5sin[1.8y+(5.4×106)t]j^\overrightarrow B = 5sin [1.8y +(5.4×10^6)t]\hat j

Answer

B→=1.33×10−8sin[1.8y+(5.4×106)t]ı^\overrightarrow B=1.33×10^{-8}sin [1.8y +(5.4×10^6)t]î

Explanation

Solution

The correct option is(A):B→=1.33×10−8sin[1.8y+(5.4×106)t]ı^\overrightarrow B=1.33×10^{-8}sin [1.8y +(5.4×10^6)t]î