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Question

Physics Question on Electromagnetic waves

The electric field of an electromagnetic wave in free space is represented as E=E0cos(ωtkz)i^\vec{E} = E_0 \cos(\omega t - kz) \hat{i}. The corresponding magnetic induction vector will be:

A

B=E0Ccos(ωtkz)j^\vec{B} = E_0 C \cos(\omega t - kz) \hat{j}

B

B=E0Ccos(ωtkz)j^\vec{B} = \frac{E_0}{C} \cos(\omega t - kz) \hat{j}

C

B=E0Ccos(ωt+kz)j^\vec{B} = E_0 C \cos(\omega t + kz) \hat{j}

D

B=E0Ccos(ωt+kz)j^\vec{B} = \frac{E_0}{C} \cos(\omega t + kz) \hat{j}

Answer

B=E0Ccos(ωtkz)j^\vec{B} = \frac{E_0}{C} \cos(\omega t - kz) \hat{j}

Explanation

Solution

Since B=EC×k^\vec{B} = \frac{\vec{E}}{C} \times \hat{k}:

B=E0Ccos(ωtkx)j^\vec{B} = \frac{E_0}{C} \cos(\omega t - kx) \hat{j}