Solveeit Logo
Login

Question

Physics Question on Magnetic properties of materials

The electric field intensity just sufficient to balance the earth's gravitational attraction on an electron will be: (given mass and charge of an electron respectively are 9.1×10−31 kg9.1 \times 10^{-31}\, kg and 1.6×10−19C)\left.1.6 \times 10^{-19} C \right).

A

−5.6×10−11N/C- 5.6 \times10^{-11} N/C

B

−4.8×10−15N/C- 4. 8 \times10^{-15} N/C

C

−1.6×10−19N/C- 1. 6 \times10^{-19} N/C

D

−3.2×10−19N/C- 3. 2 \times10^{-19} N/C

Answer

−5.6×10−11N/C- 5.6 \times10^{-11} N/C

Explanation

Solution

−eE=mg- eE = mg
E⃗=−9.1×10−13×101.6×10−19\vec{E} = - \frac{9.1 \times10^{-13}\times10}{1.6 \times10^{-19} }
=−5.6×10−11N/C= - 5.6 \times10^{-11} N/C