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Question

Physics Question on Electromagnetic waves

The electric field in an electromagnetic wave is given by E=56.5 sinω(txc) NC1E = 56.5\ sin ω(t – \frac xc)\ NC^{–1}. Find the intensity of the wave if it is propagating along x-axis in the free space. (Given 0=8.85×1012C2N1m2∈_0 = 8.85 × 10^{–12} C^2N^{–1}m^{–2})

A

5.65 Wm25.65\ Wm^{–2}

B

4.24 Wm24.24\ Wm^{–2}

C

1.9×107 Wm21.9 × 10–7\ Wm^{–2}

D

56.5 Wm256.5\ Wm^{–2}

Answer

4.24 Wm24.24\ Wm^{–2}

Explanation

Solution

Intensity of the wave,
I=12ε0E02cI = \frac 12ε_0E^2_0c
I=12×8.5×1012×(56.5)2×3×108I = \frac 12 \times 8.5 \times 10^{-12} \times (56.5)^2 \times 3 \times 10^8
I=4.24 w/m2I= 4.24\ w/m^2

So, the correct option is (B): 4.24 Wm24.24\ Wm^{–2}