Solveeit Logo

Question

Physics Question on potential energy

The electric field in a region is given by E=(Ax3)i^\overrightarrow {E} = \left(\frac{A}{x^{3}}\right) \hat{i} An expression for the potential in the region assuming the potential at infinity to be zero is

A

A2x3\frac{A}{2x^{3}}

B

2x3A\frac{2x^{3}}{A}

C

A22x\frac{A^{2}}{2x}

D

A22x2\frac{A^{2}}{2x^{2}}

Answer

A22x2\frac{A^{2}}{2x^{2}}

Explanation

Solution

Given, E=AX3iE = \frac{A}{X^3} i
We know that,
E=dvdxE = - \frac{dv}{dx}
dv=Edx\int dv = - \int - E dx
V=(Ax3)dxV = -\int(\frac{A}{x^3}) dx
V=12Ax2V = \frac{1}{2} \cdot \frac{A}{x^2}