Solveeit Logo

Question

Physics Question on Electric Dipole

The electric field due to an electric dipole at a distance rr from its centre in axial position is EE. If the dipole is rotated through an angle of 9090^{\circ} about its perpendicular axis, the electric field at the same point will be

A

EE

B

E4\frac{E}{4}

C

E2\frac{E}{2}

D

2E2E

Answer

E2\frac{E}{2}

Explanation

Solution

When a dipole ABA B of very small length is taken, then for a point PP located at a distance rr from the axis the electric field is given by
E=14πε02pr3E =\frac{1}{4 \pi \varepsilon_{0}} \cdot \frac{2 p}{r^{3}}
where pp is dipole moment. When dipole is rotated by 9090^{\circ},
then electric field is given by
E=14πε0pr3E ' =\frac{1}{4 \pi \varepsilon_{0}} \cdot \frac{p}{r^{3}} ..(ii)
From Eqs. (i) and (ii), we get
E=E2E =\frac{E}{2}