Question

The electric field due to a uniformly charged sphere of radius $R$ as a function of the distance from its centre is represented graphically by

• A.
• B.
• C.
• D.

Answer 1

Answer: (B)

Answer 2

Outside the spherical charge, the intensity of electric field at a point $P$ situated at a distance $r$ from the centre of the charge is $E=\frac{1}{4 \pi \varepsilon_{0}} \frac{q}{r^{2}} (\text { if } r>R)$ On the surface of spherical charge the electric field is given by $E=\frac{1}{4 \pi \varepsilon_{0}} \frac{q}{r^{2}}$ (if $r=R )$ and inside the spherical charge the electric field is $E=\frac{1}{4 \pi \varepsilon_{0}} \frac{q r}{R^{3}}$ (if $r < R)$ Hence, the variation of $E-r$ is a follows :