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Question

Physics Question on Electric Field

The electric field components in the given figure are Ex=αx1/2E_x = \alpha x^{1/2}, Ey=Ez=0E_y = E_z = 0 in which α=800NC1m1/2\alpha = 800\, N\, C^{-1}\, m^{-1/2}. The charge within the cube if net flux through the cube is 1.05Nm2C11.05\, N\, m^2\,C^{-1} (assume a=0.1ma = 0.1\, m)

A

9.27×1012C9.27 \times 10^{-12}\, C

B

9.27×1012C9.27 \times 10^{12}\, C

C

6.97×1012C6.97 \times 10^{-12}\, C

D

6.97×1012C6.97 \times 10^{12}\, C

Answer

9.27×1012C9.27 \times 10^{-12}\, C

Explanation

Solution

By Gauss?? law, ϕ=qε0\phi=\frac{q}{\varepsilon_{0}} or q=ϕε0q=\phi\varepsilon_{0} =1.05×8.854×1012C=1.05\times8.854\times10^{-12}\,C =9.27×1012C=9.27\times10^{12}\,C