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Question

Physics Question on Electromagnetic waves

The electric field associated with an e. mm. wave in vacuum is given by E=i^40cos(kz6×108t)\vec{ E }=\hat{ i } 40 \cos \left( kz -6 \times 10^{8} t \right), where E,zE , z and tt are in volt /m/ m, meter and seconds respectively. The value of wave vector kk is :

A

2m12\, m^{-1}

B

0.5m10.5\, m^{-1}

C

6m16\, m^{-1}

D

3m13\, m^{-1}

Answer

2m12\, m^{-1}

Explanation

Solution

Equation of Electromagnetic wave is E=E0cos(kzωt)E = E _{0} \cos ( kz -\omega t ) and speed of EM wave V=ωkV =\frac{\omega}{ k } By comparing k=ω/v=6×1083×108=2m1k =\omega / v =\frac{6 \times 10^{8}}{3 \times 10^{8}}=2 m ^{-1} is the wave vector.