Question

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by $E _x= E _{ o } \sin ( kz -\omega t )$ $B _y= B _0 \sin ( kz -\omega t )$ Then the correct relation between $E _0$ and $B _0$ is given by

• A. $E_0 B_0=\omega k$
• B. $E _0= kB _{ 0}$
• C. $kE _{ 0 }=\omega B _{ 0 }$
• D. $\omega E _{ 0 }= kB _{ 0 }$

Answer 1

Answer: (C)

$kE _{ 0 }=\omega B _{ 0 }$

Answer 2

The correct answer is (C) : $kE _{ 0 }=\omega B _{ 0 }$
C=kω​=B0​E0​​