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Physics Question on elastic moduli

The elastic behavior of material for linear stress and linear strain, is shown in the figure. The energy density for a linear strain of 5×10–4 is ____ kJ/m3. Assume that material is elastic up to the linear strain of 5×10–4
elastic behavior of material for linear stress and linear strain

Answer

μd=12×Υ×(strain)2\mu_d = \frac{1}{2} \times \Upsilon \times (\text{strain})^2

12×(201010)×(5×104)2\frac{1}{2} \times \left( \frac{20}{10^{ - 10} }\right) \times \left(5 \times 10^{-4}\right)^2

= 1011×25×10810^{11} × 25 × 10^{–8}
=25×103J/m3= 25 × 10^3 J/m^3
=25 kJ/m3= 25\ kJ/m^3