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Question

Physics Question on cells

The efficiency of fuel cell is given by the expression, η\eta is

A

η=−nFEcell ΔH×100\eta=-\frac{ nF E _{\text {cell }}}{\Delta H } \times 100

B

η=−nFEcell ΔS×100\eta=-\frac{n F E_{\text {cell }}}{\Delta S} \times 100

C

η=−nFEcell ΔA×100\eta=-\frac{ nFE _{\text {cell }}}{\Delta A } \times 100

D

None of the above

Answer

η=−nFEcell ΔH×100\eta=-\frac{ nF E _{\text {cell }}}{\Delta H } \times 100

Explanation

Solution

Efficiency of fuel cell is η=−nFEcell ΔH×100\eta=-\frac{ nFE _{\text {cell }}}{\Delta H } \times 100.
The thermodynamic efficiency of the fuel cell is the ratio of the electrical free energy to the enthalpy change of the reaction.
η=ΔGΔH×100\eta=\frac{\Delta G }{\Delta H } \times 100
Also, ΔG=−nFEcell \Delta G =- nFE _{\text {cell }}