Question

The efficiency of Carnot engine is $50 \%$ and temperature of sink is 500 K. If temperature of source is kept constant and its efficiency raised to $60 \%,$ then the required temperature of sink will be :-

• A. 100 K
• B. 600 K
• C. 400 K
• D. 500 K

Answer 1

Answer: (C)

400 K

Answer 2

$\% n=\left(1-\frac{T_{2}}{T_{1}}\right) \times 100$
For $50 \% \frac{50}{100}=1-\frac{500}{T_{1}}$
$\Rightarrow T_{1}=1000 \,K$
For $60 \% \frac{60}{100}=1-\frac{T_{2}}{1000}$
$\Rightarrow T_{2}=400 \,K$