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Question

Chemistry Question on Thermodynamics terms

The efficiency of an ideal heat engine working between the freezing point and boiling point of water, is

A

0.125

B

26.8 %

C

6.25 %

D

0.2

Answer

26.8 %

Explanation

Solution

Efficiency of ideal heat engine , η=(1T2T1)\eta = \left(1- \frac{T_{2}}{T_{1}}\right)
T2T_2: Sink temperature
T1T_1 : Source temperature
%η=(1T2T1)×100\% \eta = \left(1- \frac{T_{2}}{T_{1}} \right)\times100
=(1273373)×100= \left(1- \frac{273}{373}\right) \times100
=(100373)×100=26.8%= \left(\frac{100}{373}\right) \times100 = 26.8 \%