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Question

Physics Question on Thermodynamics

The efficiency of a Carnot engine which operates between the two temperature T1=500KT_1 = 500\, K and T2=300KT_2 = 300\, K is

A

0.5

B

0.25

C

0.75

D

0.4

Answer

0.4

Explanation

Solution

Given, T1=500KT_{1}=500\, K
T2=300KT_{2}=300\, K
We know that, efficiency of a Camot engine,
=[1T2T1]×100=\left[1-\frac{T_{2}}{T_{1}}\right] \times 100
=[1300500]×100=\left[1-\frac{300}{500}\right] \times 100
=0.4×100=0.4 \times 100
=40%=40 \%