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Question

Physics Question on Electromagnetic induction

The effective resistance across the points A and I is

A

2Ω2 \Omega

B

1Ω1 \Omega

C

0.5Ω0.5 \Omega

D

5Ω5 \Omega

Answer

1Ω1 \Omega

Explanation

Solution

The given circuit reduces to equivalent resistance of 4 Ω\Omega each connected in parallel, hence
40mm1R=14+14+14+1440\,mm \frac{1}{R} = \frac{1}{4} + \frac{1}{4} + \frac{1}{4} + \frac{1}{4}
30mm1R=44\Rightarrow \, 30\,mm \frac{1}{R} = \frac{4}{4}
30mmR=1Ω\Rightarrow 30\,mm R = 1 \Omega