Question

The eccentricity of the hyperbola

9x² – 16y² –18x –64y – 199 = 0 is

• A. 16/9
• B. 5/4
• C. 25/16
• D. Zero

Answer 1

Answer: (B)

5/4

Answer 2

$\frac{(x - 1)^{2}}{16}$–$\frac{(y + 2)^{2}}{9}$= 1

e = $\sqrt{1 + \frac{b^{2}}{a^{2}}}$= $\sqrt{1 + \frac{9}{16}}$= $\frac{5}{4}$