Question

The eccentricity of the conic 2x² + 3y² – 4x + 5y + 4 = 0 is-

• A. $\frac{1}{2}$
• B. $\frac{1}{\sqrt{2}}$
• C. $\frac{1}{3}$
• D. $\frac{1}{\sqrt{3}}$

Answer 1

Answer: (D)

$\frac{1}{\sqrt{3}}$

Answer 2

2x² + 3y² – 4x + 5y + 4 = 0

2(x–1)² + 3(y+5/6)² = $\frac{1}{12}$

$\frac{(x–1)^{2}}{1/24}$ + $\frac{(y + 5/6)^{2}}{1/36}$ = 1 Ž a² = 1/24 ; b² = 1/36