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Question: The ease of dehydrohalogenation of alkyl halide with alcoholic KOH is...

The ease of dehydrohalogenation of alkyl halide with alcoholic KOH is

A

3∘<2∘<1∘3{^\circ} < 2{^\circ} < 1{^\circ}

B

3∘>2∘>1∘3{^\circ} > 2{^\circ} > 1{^\circ}

C

3∘<2∘>1∘3{^\circ} < 2{^\circ} > 1{^\circ}

D

3∘>2∘<1∘3{^\circ} > 2{^\circ} < 1{^\circ}

Answer

3∘>2∘>1∘3{^\circ} > 2{^\circ} > 1{^\circ}

Explanation

Solution

The ease of dehydrohalogenation of alkyl halides with alcoholic KOH is 3° > 2° > 1°,

This order of alkyl halides can be explained on the basis of the stability of the alkene formed after dehydrohalogenation of haloalkanes. 3° alkyl halides on dehydrohalogenation forms more substituted alkenes, which is more stable (and formed at faster rate), while primary alkyl halides yield least substituted alkenes, which is less stable (and formed at slower rate.)