Question

The earth's magnetic field at a certain place has a horizontal component 0.3 Gauss and the total strength 0.5 Gauss. The angle of dip is

• A. $\tan ^ { - 1 } \frac { 3 } { 4 }$
• B. $\sin ^ { - 1 } \frac { 3 } { 4 }$
• C. $\tan ^ { - 1 } \frac { 4 } { 3 }$
• D. $\sin ^ { - 1 } \frac { 3 } { 5 }$

Answer 1

Answer: (C)

$\tan ^ { - 1 } \frac { 4 } { 3 }$

Answer 2

$B ^ { 2 } = B _ { V } ^ { 2 } + B _ { H } ^ { 2 } \Rightarrow B _ { V } = \sqrt { B ^ { 2 } - B _ { H } ^ { 2 } } = \sqrt { ( 0.5 ) ^ { 2 } - ( 0.3 ) ^ { 2 } } = 0.4$

Now $\phi = \tan ^ { - 1 } \left( \frac { 4 } { 3 } \right)$