Question

The earth (mass $\left. = 6 \times 10 ^ { 24 } \mathrm {~kg} \right)$) revolves round the sun with angular velocity $2 \times 10 ^ { - 7 } \mathrm { rad } / \mathrm { s }$ in a circular orbit of radius $1.5 \times 10 ^ { 8 } \mathrm {~km}$. The force exerted by the sun on the earth in newtons, is

• A. $18 \times 10 ^ { 25 }$
• B. Zero
• C. $27 \times 10 ^ { 39 }$
• D. $36 \times 10 ^ { 21 }$

Answer 1

Answer: (D)

$36 \times 10 ^ { 21 }$

Answer 2

$m = 6 \times 10 ^ { 24 } \mathrm {~kg}$ $\omega = 2 \times 10 ^ { - 7 } \mathrm { rad } / \mathrm { s }$ $R = 1.5 \times 10 ^ { 11 } \mathrm {~m}$

The force exerted by the sun on the earth

By substituting the value we can get,