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Question: The door of an almirah is 6ft high, 1.5 ft wide and weights 8 kg. The door is supported by two hinge...

The door of an almirah is 6ft high, 1.5 ft wide and weights 8 kg. The door is supported by two hinges situated at a distance of 1 ft from the ends. Assuming forces exerted on the hinges are equal, the magnitude of the force is

A

15 N

B

10 N

C

28 N

D

43 N

Answer

43 N

Explanation

Solution

tan θ = 23/4=83orcosθ=373\frac{2}{3/4} = \frac{8}{3}or\cos\theta = \frac{3}{\sqrt{73}}

Taking torque about O

8g(34)\left( \frac{3}{4} \right) = 4F cos Q

6g = 4F(373)orF=573=43N\left( \frac{3}{\sqrt{73}} \right)or ⥂ F = 5\sqrt{73} = 43N