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Question: The domain of the function \(f(x) = \sin^{- 1}\lbrack\log_{2}(x/2)\rbrack\) is...

The domain of the function f(x)=sin1[log2(x/2)]f(x) = \sin^{- 1}\lbrack\log_{2}(x/2)\rbrack is

A

[1, 4]

B

[– 4, 1]

C

[– 1, 4]

D

None of these

Answer

1,41, 4

Explanation

Solution

f(x)=sin1[log2(x/2)]f(x) = \sin^{- 1}\lbrack\log_{2}(x ⥂ / ⥂ 2)\rbrack

Domain of sin1x\sin^{- 1}x isx[1,1]x \in \lbrack - 1,1\rbrack

1log2(x/2)1- 1 \leq \log_{2}(x/2) \leq 112x22\frac{1}{2} \leq \frac{x}{2} \leq 21x41 \leq x \leq 4

x[1,4]x \in \lbrack 1,4\rbrack.