Question
Question: The domain of the function \(f\left( x \right)=\ln \left( x-\left[ x \right] \right)\) is: (1) \(...
The domain of the function f(x)=ln(x−[x]) is:
(1) R
(2) R−Z
(3) (0,+∞)
(4) Z
Solution
Here in this question we have been asked to find the domain of the given function f(x)=ln(x−[x]) . The definition of the domain of a function is the set of all possible inputs for the function. Now for answering this question we will find the possible values of x .
Complete step by step answer:
Now considering from the question we have been asked to find the domain of the given function f(x)=ln(x−[x]) .
From the basic concepts of functions, we know that the definition of the domain of a function is the set of all possible inputs for the function.
From the basic concepts of logarithms, we know that the logarithm is defined as logbx=y⇒by=x where x,b>0 and b=1 .
In the given function, the base is e it satisfies the conditions of logarithms and here x−[x]>0should be valid for satisfying the conditions of logarithms.
We know that [x] is the greatest integer function which is defined as the greatest integer value that is less than or equal to x . For example [−1.5]=−2 and [2.7]=2 .
We can say that x-\left[ x \right]=\left\\{ \begin{matrix}
\text{0, if x is an integer} \\\
\text{decimal part of x, if a is a positive non-integer} \\\
\text{(1- decimal part of x), if a is a negative non-integer} \\\
\end{matrix} \right\\}.
Since x−[x]>0 it implies that x>[x] is valid when x is not a perfect integer.
Therefore we can conclude that the domain of the given function f(x)=ln(x−[x]) is R−Z .
So, the correct answer is “Option 2”.
Note: While answering questions of this type we should be sure with our concepts that we are going to apply in between the steps. If someone had a misconception and considered [−1.5]=−1 then they will end up having no conclusion for the question because they will say that x-\left[ x \right]=\left\\{ \begin{matrix}
\text{0, if x is an integer} \\\
\text{decimal part of x, if a is a positive non-integer} \\\
\text{(- decimal part of x), if a is a negative non-integer} \\\
\end{matrix} \right\\}
Which is a wrong statement leading to the conclusion that the domain will be (0,∞)−Z which is not in the options.