Question
Question: The distribution coefficient, \({{K}_{D}}\) for an organic compound between water and methylene chlo...
The distribution coefficient, KD for an organic compound between water and methylene chloride is 3.40. An aqueous solution of the organic compound contains 0.500g per 100 mL and is extracted with 50.0 mL of methylene chloride. What percentage of the organic compound originally in water is extracted?
(A) \ 31.5\% \\\
(B) \ 63.0\% \\\
(C) \ 72.0\% \\\
(D) \ 92.6\% \\\
Solution
Distribution coefficient is the ratio of concentration of two immiscible solvent mixtures which are in equilibrium. It compares solubility of solute in two liquids. Concentration is the ratio of mass of solute in g to Volume. Distribution coefficient is obtained by dividing concentration of solute in organic phase to in aqueous phase.
Complete step by step answer:
- Consider xg of organic compound extracted in methylene chloride.
- Amount of organic compounds remaining in water in0.5−x g.
- As x g of organic compound is extracted in 50mLof methylene chloride and in aqueous solution the amount of organic compound present is0.5−x in 100mL.
- As we know, the distribution coefficient is the ratio of concentration of solute in organic solvent to concentration of solute in aqueous.
- Concentration in methylene chloride=50mLx
- Concentration in water =100mL0.5−x
As given distribution coefficient Kd=3.40
So we can write,
Kd=50mLx×0.5−x100mL=3.40
0.5−x2x=3.400.5−xx=1.70x =0.85- 1.70 x2.70x=0.85x=0.315
So, 0.315 g of organic compound is extracted in water and 0.185 g of organic compound is extracted in methylene chloride.
The percentage of organic compound originally extracted in water is
=0.5x×100