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Question

Question: The distance travelled s (in metre) by a particle in t second is given by \(s = t^{3} + 2t^{2} + t\)...

The distance travelled s (in metre) by a particle in t second is given by s=t3+2t2+ts = t^{3} + 2t^{2} + t. The speed of the particle after 1 sec. will be

A

8 cm/sec.

B

6 cm/sec.

C

2 cm/sec

D

None of these

Answer

8 cm/sec.

Explanation

Solution

s=t3+2t2+ts = t^{3} + 2t^{2} + t, v=dsdt=3t2+4t+1v = \frac{ds}{dt} = 3t^{2} + 4t + 1

Speed of the particle after 1 second

v(t=1)=(dsdt)(t=1)=3×12+4×1+1=8cm/sec.v_{(t = 1)} = \left( \frac{ds}{dt} \right)_{(t = 1)} = 3 \times 1^{2} + 4 \times 1 + 1 = 8cm/sec.