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Question

Question: The distance of the point 'q' on the ellipse \(\frac{x^{2}}{a^{2}}\)+ \(\frac{y^{2}}{b^{2}}\)= 1 fro...

The distance of the point 'q' on the ellipse x2a2\frac{x^{2}}{a^{2}}+ y2b2\frac{y^{2}}{b^{2}}= 1 from a focus is-

A

a(e + cos q)

B

a(e – cos q)

C

a (1 + e cos q)

D

a(1 + 2e cos q)

Answer

a (1 + e cos q)

Explanation

Solution

Focal distance of any point P(x, y) on the ellipse is equal to SP = a + ex; Here x = a cos q

\ SP = a + e (a cos q) Ž a (1 + e cos q)