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Question: The distance of the point (b cosq, b sin q) from origin is-...

The distance of the point (b cosq, b sin q) from origin is-

A

b cot q

B

b

C

b tan q

D

b2\sqrt{2}

Answer

b

Explanation

Solution

Distance = (bcos⁡θ–0)2+(bsin⁡θ–0)2\sqrt{(b\cos\theta –0)^{2} + (b\sin\theta –0)^{2}}

= b2cos⁡2θ+b2sin⁡2θ\sqrt{b^{2}\cos^{2}\theta + b^{2}\sin^{2}\theta}

= b