Question

The distance of the point $(6,-2 \sqrt{2})$ from the common tangent y=m x+c, m&gt0;, of the curves $x=2 y^2$ and $x=1+y^2$ is :

• A. $5 \sqrt{3}$
• B. $\frac{14}{3}$
• C. $\frac{1}{3}$
• D. 5

Answer 1

Answer: (D)

5

Answer 2

For
y2=2x​,T:y=mx+8m1​
For tangent to y2+1=x
⇒(mx+8m1​)2+1=x
D=0⇒m=22​1​
∴T:x−22​y+1=0
d=∣∣​9​6+8+1​∣∣​=5