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Question

Mathematics Question on coordinates of a point in space

The distance of the point (3, 4, 5) from X-axis is

A

3

B

5

C

34\sqrt{34}

D

41\sqrt{41}

Answer

41\sqrt{41}

Explanation

Solution

The foot of perpendicular from (3, 4, 5) on X-axis is (3, 0, 0). Hence, the required distance =(3−3)2+(4−0)2+(5−0)2=41 = \sqrt{(3 - 3)^2 + (4 - 0)^2 + (5 - 0)^2 } = \sqrt{41}.