Question

The distance of the point $(-1,9,-16)$ from the plane $2 x+3 y-z=5$ measured parallel to the line $\frac{x+4}{3}=\frac{2-y}{4}=\frac{z-3}{12}$ is

• A. $20 \sqrt{2}$
• B. 31
• C. $13 \sqrt{2}$
• D. 26

Answer 1

Answer: (D)

26

Answer 2

Equation of line
$3x+1​=−4y−9​=12z+16​$
G.P on line $(3λ−1,−4λ+9,12λ−16)$
point of intersection of line plane
$6λ−2−12λ+27−12λ+16=5$
$λ=2$
Point $(5,1,8)$
Distance $=36+64+576​=26$