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Question

Mathematics Question on Plane

The distance of the origin from the plane through the points (1,1,0)(1, 1, 0), (1,2,1)(1, 2, 1) and (2,2,1)(-2, 2, -1) is

A

311\frac{3}{\sqrt{11}}

B

522\frac{5}{\sqrt{22}}

C

33

D

422\frac{4}{\sqrt{22}}

Answer

522\frac{5}{\sqrt{22}}

Explanation

Solution

The equation of plane is x1y1z 011 311=0\begin{vmatrix}x-1&y-1&z\\\ 0&1&1\\\ -3&1&-1\end{vmatrix}=0 2x+3y3z=5\Rightarrow 2x + 3y - 3z = 5 Distance of origin (0,0,0)\left(0, 0,0\right) from the plane is 522+32+32=522\left|\frac{-5}{\sqrt{2^{2}+3^{2}+3^{2}}}\right|=\frac{5}{\sqrt{22}}.